Matematika Tolong dibantu ya Kaaa... Mksh​

Tolong dibantu ya Kaaa... Mksh​

Jawab:

Penjelasan dengan langkah-langkah:

Jawaban:

f(x) = x² + 3x - 5

f(2) = 2² + 3(2) - 5

f(2) = 5

a.

limit [f(x) - f(2)]/(x - 2)

x-->2

limit [f(x) - f(2)]/(x - 2)

x-->2

limit [(x² + 3x - 5) - (5)]/(x - 2)

x-->2

limit (x² + 3x - 10/(x - 2)

x-->2

limit (x + 5)(x - 2)/(x - 2)

x-->2

limit (x + 5)

x-->2

= 2 + 5

= 7

b.

limit [f(x + h) - f(x)]/h

h-->0

limit [(x+h)² + 3(x+h) - 5 - (x²+3x - 5)]/h

h-->0

limit [(x²+2hx + h²+ 3x + 3h - 5 - (x²+3x- 5)]/h

h-->0

limit [(x²-x²+3x - 3x + 2hx + h² + 3h - 5 + 5]/h

h-->0

limit (2hx + h² + 3h)/h

h-->0

limit h(2x + h + 3)/h

h-->0

limit (2x + h + 3)

h-->0

= 2x + 3

[answer.2.content]